A cliff diver positions herself on a cliff that angles downwards towards the edg

Question

A cliff diver positions herself on a cliff that angles downwards towards the edge. The length of the top of the cliff is41.0 m and the angle of the cliff is ? = 20.0

A cliff diver positions herself on a cliff that angles downwards towards the edge. The length of the top of the cliff is41.0 m and the angle of the cliff is ? = 20.0 degree below the horizontal. The cliff diver runs towards the edge of the cliff with a constant speed, and reaches the edge of the cliff in a time of 5.60 s. After running straight off the edge of the cliff (without jumping up), the diver falls h = 28.0 m before hitting the water. After leaving the edge of the cliff, how much time does the diver take to get to the water?

Explanation / Answer

velocity of jump=41/5.6=7.321mts/s

Vy=vsin20=2.504

Vx=vcos20=6.879m/s

a)s=ut+0.5at^2

28=2.5t+0.5*9.81*t^2

4.9t^2+2.5t-28=0

t=2.148secs

b)s=Vx*t=6.879*2.148=14.776mts

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