Question
Here is my Q
Two 12-cm-diameter electrodes 0.60cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14V battery. What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes Two 12-cm-diameter electrodes 0.60cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14V battery. What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes while the capacitor is attached to the battery? Express your answer using two significant figures. Express your answer using two significant figures. Express your answer using two significant figures. Express your answer using two significant figures. After insulating handles are used to pull the electrodes away from each other until they are 1 4cm apart? The electrodes remain connected to the battery during this process. Express your answer using two significant figures. Two 12-cm-diameter electrodes 0.60cm apart form a parallel-plate capacitor. The electrodes are attached by metal wires to the terminals of a 14V battery. What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes Express your answer using two significant figures. Express your answer using two significant figures. Express your answer using two significant figures. After the original electrodes (not the modified electrodes of part D) are expanded until they are 22cm in diameter while remaining connected to the battery'? Express your answer using two significant figures. Express your answer using two significant figures.
Explanation / Answer
the separation between the electrodes is d they form a parallel plate capacitor the capacitance is C = (e_o x A/d) where e_o = 8.85 x 10^-12 C^2/Nm^2 and A is area of the plates the charge on the plates is Q = C x V where V is the applied potential difference the electric field between the plates is E = (V/d) the energy stored in the capacitor is U = (1/2)C x V^2
