1.Three point charges are on the x axis: q 1 = -6.0 A positively charged particl

Question

1.Three point charges are on the x axis: q1 = -6.0

A positively charged particle is free to move in a region with an electric field E. Which statement(s) must be true? (a) The particle is accelerating in the direction perpendicular to E. -Select- (b) The particle is accelerating in the direction of E. -Select- (c) The particle is moving in the direction of E. -Select- (d) The particle is momentarily at rest. -Select- (e) The force on the particle is opposite the direction of E. -Select- (f) The particle is moving opposite the direction of E. -Select- True or False: (a) The electric field of a point charge always points away from the charge. True False (b) The electric force on a charged particle in an electric field is always in the same direction as the field. True False (c) Electric field lines never intersect. True False (d) All molecules have dipole moments in the presence of an external electric field. True False Four charges are fixed in place at the corners of a square as shown below. No other charges are nearby. Which of the following statements is true? E is zero at the center of the square E is zero midway between the top two charges and midway between the bottom two charges E is zero at the midpoints of all four sides of the square A small 13.6 g plastic ball is suspended by a string in a uniform horizontal electric field with a magnitude 1.00 x 103 N/C. If the ball is in equilibrium when the string makes a 30 degree angle with the vertical, what is the net charge on the ball?

Explanation / Answer

force on q1 due to q2 = F = Ke * q1 * q2 / r2 = -0.0479 N

force on q1 due to q3 = 0.00599 N

net force on q1 = -0.0479 + 0.00599 = -0.04191 N

2. a) false

b) true

c) true

d) false

e)false

f) false

3. a) false

b) false

c) true

d)true

4. E is zero at the center of the square

5. let the tension in the string be T.

Tcos(30) = mg

T = [13.6*9.8*10^-3]/cos(30) N

now Let the charge on the ball be q. then

Tsin(30) = E*q

13.6*9.8*10^-3*tan(30) = 10^3 * q

q = 7.67*10^-5 c

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