2.10 times 10-9 C charge has coordinates x = 0, y = ?2.00; a 2.97 times 10-9 C c
ID: 2128615 • Letter: 2
Question
2.10 times 10-9 C charge has coordinates x = 0, y = ?2.00; a 2.97 times 10-9 C charge has coordinates x = 3.00, y = 0; and a-4.85 times 10-9 C charge has coordinates x = 3.00, y = 4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin and the instantaneous acceleration of a proton placed at the origin. Determine the magnitude and direction for the electric field at the origin (measure the angle counterclockwise from the positive x-axis) Determine the magnitude and direction for the instantaneous acceleration of a proton placed at the origin (measure the angle counterclockwise from the positive x-axis).Explanation / Answer
EF AT ORIGIN DUE TO 2.1 is E1 = kq/r^2 = 9e9 * 2.1*10^-9/2^2 = 4750 N/C
Ef at orign a]due to 2.97 charge is E2 = 9e9* 2.97/9 = 2970 N/C
resulatnat of tehse two fields is E = sqrt(E1^2 +E2^2)
E = 5602 N/C
E3 due to -4,84 = 9e9* 4.84nC/0.05^2 =-17424 N/C
Enet = -11822 N/C direction = -71.9 deg
b.
acclearation for proton a = Eq/m = 11822 * 1.6*10^-19/1.6*10^-27 =1.13*10^12 m/s^2
agnle = -71.9 deg = 288.1 from +ve x axis
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