http://imgur.com/Dn8u74R In the above picture, a box is suspended by two strings

Question

http://imgur.com/Dn8u74R

In the above picture, a box is suspended by two strings that are attached at the same point. The long string goes over the outer pulleys and under the central pulley. Both ends of the long string are attached to the weight. The tension in the long string is T = 244 N. The box has a mass of M = 52 kg, and the central pulley has mass m = 5 kg. The outer pulleys are suspended from the ceiling. The angle ? of the long string with respect to the vertical axis in the lower part of the system is ? = 25 degrees. If the system is in balance, what is the angle ? that the long string makes with respect to the horizontal in the upper part of the system? [In your calculation, use g = 9.8 m/s2.]

In the above picture, a box is suspended by two strings that are attached at the same point. The long string goes over the outer pulleys and under the central pulley. Both ends of the long string are attached to the weight. The tension in the long string is T = 244 N. The box has a mass of M = 52 kg, and the central pulley has mass m = 5 kg. The outer pulleys are suspended from the ceiling. The angle ? of the long string with respect to the vertical axis in the lower part of the system is ? = 25 degrees. If the system is in balance, what is the angle ? that the long string makes with respect to the horizontal in the upper part of the system? [In your calculation, use g = 9.8 m/s2.]

Explanation / Answer

Answer question

2*T*cos(25)+2*Tsin(theta) = (m+M)*g

cos25+sin(theta) = 57*9.8/(488)

theta= 13.79 = 13.8 degrees

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