In the figure, four charges, given in multiples of 9.0010 -6 C form the corners

Question

In the figure, four charges, given in multiples of 9.0010-6 C form the corners of a square and four more charges lie at the midpoints of the sides of the square. The distance between adjacent charges on the perimeter of the square is d = 3.0010-2 m. What are the magnitude and direction of the electric field at the center of the square?(A) The magnitude of E?

(B)Ex?

(C)Ey?

In the figure, four charges, given in multiples of 9.00 times 10-6 C form the corners of a square and four more charges lie at the midpoints of the sides of the square. The distance between adjacent charges on the perimeter of the square is d = 3.00 times 10-2 m. What are the magnitude and direction of the electric field at the center of the square?(A) The magnitude of E?

Explanation / Answer

due to -5q

E1x = k*5*q*cos45/4d^2.............E1y = k*5*q*sin45/4d^2

due to +5q

E2x = k*5*q*cos45/4d^2.............E2y = k*5*q*sin45/4d^2

due to -2q

E3x = k*2*q*/d^2.............E3y = 0

due to +q.on -x axis

E4x = k*q*/d^2.............E4y = 0

due to +3q on lower right

E5x = -k*5*q*cos45/4d^2.............E5y =+ k*5*q*sin45/4d^2

due to +3q on lower right

E6x = +k*5*q*cos45/4d^2.............E6y =-k*5*q*sin45/4d^2

due to +q.on +y axis

E7x = 0.............E7y = -k*q*/d^2


due to +q.on -y axis

E8x = 0.............E8y = k*q*/d^2

Exnet

Ex = 2*k*3q/d^2 +k*2*5*q*cos45/4d^2

= (k*q/d^2)*((6+10*cos45/4))

= 69.909*10^7 N/C
Eynet
Ey = k*2*5*q*cos45/4d^2 = 15.909*10^7N/C

Ex = 2*k*3q/d^2 +k*2*5*q*cos45/4d^2

= (k*q/d^2)*((6+10*cos45/4))=

= 69.909*10^7 N/C

Ey = k*2*5*q*sin45/4d^2 = 15.909*10^7N/C

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