Consider a box of mass 125.0 kg. It is on a frictionless surface. Dr. B is pulli

Question

Consider a box of mass 125.0 kg. It is on a frictionless surface.  Dr. B is pulling with a force of 75.0 N at an angle of 22.0 degrees above the horizontal to the right, and Dr. Wig is pulling with a force 12.5 N to the left.

   a. Draw a picture of this situation

   b. ID all the forces acting on the box

   c. Define a coordinate system

   d. Which force do you need to do trig on?

          i. Do the trig on that force, replacing it with an x and y force

   e. Write N2 for each of the coordinates

   f. Solve for the normal force, the weight, and the acceleration of the box.

Explanation / Answer

75 N acting at angle of 22 degrees above horizontal

so 75cos22 =69.54 N horizontally (right direction)

and 75sin22 = 29.10 vertically (upward) .. components by Dr. B's force

dr. A 12.5 N to leftwards

weight = mg = 125g =1225 N downwards

Normal reaction N upwards.

N = mg - 75sin22 = 1195.9 N

a = 69.54- 12.5 /125 = 0.0445 m/s2 in right direction

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