When a parachute opens, the air exerts a large drag force on it. This upward for

Question

When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the sky diver and, thus, slows him down. Suppose the weight of the sky diver is 868 N and the drag force has a magnitude of 1022 N. The mass of the sky diver is 88.6 kg. Take upward to be the positive direction. What is his acceleration, including sign?

When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the sky diver and, thus, slows him down. Suppose the weight of the sky diver is 868 N and the drag force has a magnitude of 1022 N. The mass of the sky diver is 88.6 kg. Take upward to be the positive direction. What is his acceleration, including sign? Number Units the tolerance is +/-2%

Explanation / Answer

resulataNT FORCE F = 1022-868 = 154 N

as F = ma

a = 154/88.6   =1.738 m/s^2

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