Please answer both parts correctly and provide an adequate explanation. Thank yo

Question

Please answer both parts correctly and provide an adequate explanation. Thank you.

In the figure below, the voltage source is 120 V, the wire resistance is 0.400Ohm, and the bulb is nominally 61.8 W. When the motor (which has a low resistance) comes on, a large current flows causing a significant voltage drop in the wire. The reduces the voltage received by the bulb and causes it to dim noticeably. What power will the bulb dissipate if a total of 30.8 A passes through the wires when the motor comes on? Assume negligible change in bulb resistance. W What power is consumed by the motor? kW

Explanation / Answer

power = i^2 R = 30.8^2 * 0.4 = 380 watts

power consumed by motor = 380-61.8 = 318.2 Watts

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