A 6 N horizontal force F pushes a block weighing 14.0 N against a vertical wall

Question

A 6 N horizontal force F pushes a block weighing 14.0 N against a vertical wall (Fig. 6-21). The coefficient of static friction between the wall and the block is 0.61, and the coefficient of kinetic friction is 0.41. Assume that the block is not moving initially.

(a) What is the normal force exerted on the block by the wall? Give in unit vector notation.

(b) Will the block move?

(c) If Yes, what is the acceleration of the block in unit vector notation? If No, what is the friction force in unit vector notation?Assume the units are m/s2 for acceleration and N for force.

A 6 N horizontal force F pushes a block weighing 14.0 N against a vertical wall (Fig. 6-21). The coefficient of static friction between the wall and the block is 0.61, and the coefficient of kinetic friction is 0.41. Assume that the block is not moving initially. What is the normal force exerted on the block by the wall? Give in unit vector notation. What is the normal force exerted on the block by the wall? Give in unit vector notation. Will the block move? If Yes, what is the acceleration of the block in unit vector notation? If No, what is the friction force in unit vector notation?Assume the units are m/s2 for acceleration and N for force.

Explanation / Answer

normal force on the block = F = 6N

a) 6i+0j

b) yes

fi ictional force = Us*N =0.61*6=3.66N...in upward direction

here 3.66 is less than 14 N so the block will move

F net = 14-f = 14-3.66 =10.34 N

a = Fnet / m = 10.34/(14/9.8) = 7.238 -j

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