The diagram below shows two vectors, A and B, and their angles relative to the c
ID: 2132774 • Letter: T
Question
- The diagram below shows two vectors, A and B, and their angles relative to the coordinate axes as indicated.
- http://capa-new.colorado.edu/msuphysicslib/Graphics/Gtype07/prob01a_vectors2.gif
- DATA: alpha = 44.5 degrees, beta = 54.8 degrees, A = 2.70 cm.
- The vector A - B is parallel to the -x axis (points due West). Calculate the y component of vector B.
PART 2:
- Calculate the x component of the vector A -B.
PART 3:Calculate the magnitude of the vector A + B.
PART 2:
- Calculate the x component of the vector A -B.
PART 3:Calculate the magnitude of the vector A + B.
The diagram below shows two vectors, A and B, and their angles relative to the coordinate axes as indicated. DATA: alpha = 44.5 degrees, beta = 54.8 degrees, A = 2.70 cm. The vector A - B is parallel to the -x axis (points due West). Calculate the y component of vector B. Calculate the x component of the vector A -B. Calculate the magnitude of the vector A + B.
Explanation / Answer
A - B is parallel to the -x axis
so
A*sin(alpha)=B*cos(beta)
2.7*sin(44.5)=|B|*cos(54.8)
|B|=3.283
By=-|B|*cos(54.8) j=-1.89 (j)
(A-B)x=Ax - Bx=
-|A|*cos(44.5) - |B|*sin(54.8)=
=-1.925 (i)
|A+B|=sqrt((Ax+Bx)^2 + (Ay+By)^2)
=sqrt((21.24+14.33))
=5.96 (Cm)
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