A new capacitance is formed by attaching two uncharged metal plates, each with a

Question

A new capacitance is formed by attaching two uncharged metal plates, each with area A. The battery remains connected.

The left plate has charge -Q, the right plate has charge +Q, separated by distance d.

1. When the new plates are attached, does the electrical potential difference between the two plates inc, dec, or stay the same?

2. Write an expression for the work done by the e-field on a charge +q as it travels from the left plate of the capacitor on the right. Express the answer in terms of the given variables.

3. Write an expression for the magnitude and direction of the e-field between the plates. Is the magnitude of the E-field greater, less, or equal to the E-field between the plates before the new plates were attached?

4. Write an expression for the charge density on the plates of the capacitor. Is the charge density greater, less, or equal than before the new plates were attached?

Explanation / Answer

1. remans same

2. work done W = VQ

3. Electric field E= V/d , its magnetude is same

4. surface charge denity sigma   E e0 ------------this also remains the same

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