(a) What is the coefficient of kinetic friction between the crate and the floor?

Question

(a) What is the coefficient of kinetic friction between the crate and the floor?

b)If the 700 N force is instead pulling the block at an angle of 20.0° above the horizontal as shown in Figure P4.37b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in (a). m/s2

*I found (a) but I can't seem to get the right answer for b)*

A 1200 N crate is being pushed across a level floor at a constant speed by a force Frightarrowof 700N at an angle of 20.0Adegree below the horizontal, as shown in Figure P4.37a. What is the coefficient of kinetic friction between the crate and the floor? If the 700 N force is instead pulling the block at an angle of 20.0Adegree above the horizontal as shown in Figure P4.37b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in (a). m/s2 *I found (a) but I can't seem to get the right answer for b)*

Explanation / Answer

force of friction = Fcos(theta) = 700*cos(20)

thus coeffecient of friction = 700*cos(20) / (1200 + (700*sin(20)) = 0.4569809580163338

b) force = Fcos(20) - (mg -Fsin(20)*0.4569809580163338) = 700*cos(20) - ( (1200 - (700*sin(20))*0.4569809580163338) = 218.8153698611989324475 N

thus a = 218.8153698611989324475/(1200/9.8) = 1.7869921871997912816546 m/s^2

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