An unsuspecting bird is coasting along in an easterly direction at 2.00 mph when

Question

An unsuspecting bird is coasting along in an easterly direction at 2.00 mph when a strong wind from the south imparts a constant acceleration of 0.400 m/s2.  If the acceleration from the wind lasts for 3.40 s, find the magnitude, r, and direction, ?, of the bird's displacement during this time period.  (HINT: assume the bird is originally travelling in the  x direction and there are 1609 m in 1 mile.)

Now, assume the same bird is moving along again at 2.00 mph in an easterly direction but this time the acceleration given by the wind is at a 45.0 degree angle to the original direction of motion.  If the magnitude of the acceleration is 0.300 m/s2, find the displacement vector     , and the angle of the displacement, ?1.  Enter the components of the vector and angle below.  (Assume the time interval is still 3.40 s.)

Explanation / Answer

Vb = 1.34 i meter/sec

Aw = -0.4 j m/s^2

x component of bird = 1.34 * 2.6 = 3.484 i

y component of bird = - 0.5 *0.4* 2.6*2.6 = -1.352 j

displacement = 3.484 i - 1.352 j


magnitude = 3.737 meters

angel = 338.79 degrees with + x axis in anti clock wise direction

2ND CASE


Vb = 1.34 i meter/sec

in this case two cases arised it makes 32 degrees ,but this may be in anticlock wise or clock wise so please specify that condition

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