The resistances in Figure ( a ) and Figure ( b ) are all 6.3 ?, and the batterie

Question

The resistances in Figure (a) and Figure (b) are all 6.3  ?, and the batteries are ideal 16  V batteries.

(a) When switch S in Figure (a) below is closed, what is the change in the electric potential V1 across resistor 1, or does V1 remain the same (enter "0")?

(b) When switch S in Figure (b) below is closed, what is the change in V1 across resistor 1, or does V1 remain the same (enter "0")?

The resistances in Figure (a) and Figure (b) are all 6.3 ?, and the batteries are ideal 16 V batteries. When switch S in Figure (a) below is closed, what is the change in the electric potential V1 across resistor 1, or does V1 remain the same (enter "0")? When switch S in Figure (b) below is closed, what is the change in V1 across resistor 1, or does V1 remain the same (enter "0")?

Explanation / Answer

a) yes it remains same, change in electric potential V1

net resistance = 6.3/2 = 3.15 ohms

so i = V/r = 16/3.15 = 5.08 A

so current through R1 = 5.08/2 = 2.54 A

so V1 = ir = 2.54*6.3 = 16 V

b) net resistance = 6.3*2 = 12.6 ohms

current = 16/12.6 = 1.27 A

so voltage difference = 1.27*6.3 = 8 V

after swich is closed,

net resistance = 3.15 + 6.3 = 9.45 ohms

i = 16/9.45 = 1.69 A

i through R1 = 1.69/2 = 0.85 A

so Voltage difference through R1 = 0.85*6.3 = 5.36 V

so change in v1 = 8 - 5.36 = 2.64 V

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