A 1.870 kg block of wood rests on a steel desk. The coefficient of static fricti

Question

A 1.870 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is ?s = 0.555 and the coefficient of kinetic friction is ?k = 0.205. At time t = 0, a force F = 6.26 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times:

                                                           t=0  N=?  ,  t>0 N=?

Consider the same situation, but this time the external force F is 12.6 N. Again state the force of friction acting on the block at the following times:

  t=0  N=?  ,  t>0  N=?

Explanation / Answer

force required to move the object=us *mg

=10.17 N

so at t=0, f=6.26 N

at t>0, f=6.26 N

b)force is greater than the moving force,

so,

f=uk mg

=3.75 N

at t=0, f=3.75 N

at t>0, f=3.75 N

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