detail as below A rubber ball is dropped and bounces vertically from a horizonta

Question

detail as below

A rubber ball is dropped and bounces vertically from a horizontal concrete floor. If the ball has a speed of 3.6 m/s just before striking the floor and a speed of 2.2 m/s just after bouncing, what is the average force of the floor on the ball? Assume the ball is in contact with the floor for 0.15 s and the mass of the ball is 0.11 kg. N Two objects of mass m and 7m undergo a completely inelastic collision in one dimension. If the two objects are at rest after the collision, what was the ratio of their speeds before the collision? Vm/v7m = Consider the Sun and the Earth as a "system" of two "particles". The center of mass of this system lies a distance L from the center of the Sun. Find L and compare it to the radius of the Sun. L= m The center of mass of the Earth-Sun system lies

Explanation / Answer

5)force=change in momentum

=0.11*(3.6+2.2)/0.15

=4.2533 m/s^2

6)conserving momentum,

m1v1=m2v2

or v1/v2=m2/m1

=7

7) it lies closer to the sun

L=5.97*10^24*1.49*10^11/(5.97*10^24+1.989*10^30)

=447223 m

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