1. A baseball is hit with a horizontal speed of 16 m/s and a vertical speed of 1

Question

1. A baseball is hit with a horizontal speed of 16 m/s and a vertical speed of 17 m/s upward. What are these speeds 5 s later?

horizontal speed?  m/s

verticle speed?     m/s

2. If a baseball is hit with a vertical speed of 35 m/s and a horizontal speed of 2 m/s, how long will the ball remain in the air? (Assume for the purposes of this question that the ball starts at nearly ground level.)
s

How far will it go?
m

3. A fox is chasing a bunny. The bunny is initially hopping east at 4 m/s when it first sees the fox. Over the next half second the bunny changes its velocity to west at 12 m/s and escapes. What was the bunny's average acceleration (magnitude and direction) during this half-second interval?

m/s2 ---Select--- east west

4. A tennis ball is hit with a vertical speed of 15 m/s and a horizontal speed of 40 m/s. How long will the ball remain in the air?

s

How far will it travel horizontally during this time?
m

5. Find the size and direction of the change in velocity for each of the following initial and final velocities.

Explanation / Answer

1) horizontal speed stays constant since no acceleration is present in the x direction.

the y velocity is changing due to gravity. Use the formula V(final)=V(initial)+a*t

V initial= 17 m/s

a= -9.8 m/s^2

t= 5 sec

V(final)=17-9.8*5= -32m/s

therefore the ball is traveling downward at 32m/s and horizontally at 16 m/s

2)when when vertical speed = 0 for the first time the ball is at the topmost point

so 0 = 35 - 9.8*t

t = 3.57

so total time taken = 2t = 7.14 sec

distance = v horizontal * t = 2 * 7.14 = 14.28 m

3)

4)t = 2* 15/9.8

= 3.06 sec

distance = 40* 3.06 = 122.44 m

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