1-An archer pulls her bowstring back 0.374 m by exerting a force that increases
ID: 2137884 • Letter: 1
Question
1-An archer pulls her bowstring back 0.374 m by exerting a force that increases uniformly from zero to 243 N.
An archer pulls her bowstring back 0.374 m by exerting a force that increases uniformly from zero to 243 N. What is the equivalent spring constant of the bow? How much work does the archer do on the string in drawing the bow? A force F= (6xi+ 5yj), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x direction from the origin to x = 4.82 m. Find the work done by the force on the object.
Explanation / Answer
As we know dat
F = kx
or k = F/x
= 243/.374 = 649.73
Work done = 1/2 kx^2 = 1/2 * 649.73*(.374)^2 = 45.44 J
2. work done = int (f.dx) = 3x^2dx limit from 0 to 4.82 since along x axis y = 0
= 3*4.82*4.82 = 69.69 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.