As shown in the figure below, a box of mass m = 17.6 kg is released from rest (a
ID: 2138582 • Letter: A
Question
As shown in the figure below, a box of mass m = 17.6 kg is released from rest (at position A) at the top of a 30.0
As shown in the figure below, a box of mass m = 17.6 kg is released from rest (at position A) at the top of a 30.0 degree frictionless incline. The box slides a distance d = 4.80 m down the incline before it encounters (at position B) a spring and compresses it an amount xC = 0.220 m (to point C) before coming momentarily to rest. Using energy content, determine the following. (To help with this problem, the height is sin(30 degree)*4.80 = 2.4m) speed of the box at position B vB = 6.86 m/s (I figured this out already) spring constant k = (answer needed! Has to be in N/m) ANSWER IS NOT 1.71 x 10^4 :(Explanation / Answer
a)17.6*9.8*2.4=.5*17.6*v^2
v=6.85 m/s
b)intial energy converted to final ....
.5*mv^2+mgxsin30=.5kx^2
17.6(.5*6.85^2+9.8*.22*sin30)=.5*k*.22^2
x=17846.7272=1.78*10^4
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