The wheels of a 1.450x10 3 kg car are locked so that it can only slide on wet co

Question

The wheels of a 1.450x103 kg car are locked so that it can only slide on wet concrete at a constant speed of 3.00 m/s when pulled by a horizontal force of 3.45x103 N.
A) Find the coefficient of sliding friction for rubber on wet concrete (book says for static friction is is 0.7 and for kinetic it is 0.5)
B) What is the acceleration of the car after 3.50s?
Pls can the reply be as detailed as possible with regard to how the answer was determined......I really appreciate it :) The wheels of a 1.450x103 kg car are locked so that it can only slide on wet concrete at a constant speed of 3.00 m/s when pulled by a horizontal force of 3.45x103 N.
A) Find the coefficient of sliding friction for rubber on wet concrete (book says for static friction is is 0.7 and for kinetic it is 0.5)
B) What is the acceleration of the car after 3.50s?
Pls can the reply be as detailed as possible with regard to how the answer was determined......I really appreciate it :)

Explanation / Answer

friction = u.N

and N = mg

so friction = u.mg

in horizontal ( F = ma)

3.45 x 10^3 - friction = ma

3450 - u.1450g = 1450 x 0    ( constant speed means a = 0)

u = 0.243

a a = 0

so v = 3 m/s always

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