HELP What devices are considered Ohmic devices in this experiment? Are there any

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What devices are considered Ohmic devices in this experiment? Are there any devices used in this experiment which do not appear to be an Ohmic device? Why do they not appear as if they are an Ohmic device? Resistors have power ratings. Generally, the larger the physical size of the resistor, the better that it will dissipate the amount of heat it generates. If the amount of power that the resistor can dissipate is exceeded the resistor will fail to work. Which of the following combinations will exceed the power rating of 1 Watt? Show work. A 10 Ohm resistor connected to a 3 volt battery A 50 Ohm resistor carrying a current of 100 milliamps A resistor carrying a current of 0.5 amps while a voltage of 3 volts is applied across it The voltage across a resistor is equal to the product of the current through the resistor and the resistance of the resistor. When two resistors are connected in series the same current passes through them. If a 10 Ohm resistor is connected in series with a 50 Ohm resistor and a current of 100 milliamps passes through them when a battery is connected, what are the voltages across each of these resistors? What is the potential difference of the battery? When two resistors are connected in a parallel configuration the voltages across each are the same. If the 10 Ohm resistor and the 50 Ohm resistor are connected in parallel and a battery of 3 volts is applied, both resistors will each have a potential difference of 3 volts. What are the currents through these resistors?

Explanation / Answer

1) the devices which obey ohm's law are called ohmic devices.


all the metals are ohmic materials.

2)

c) P = v*i = 3*0.5 = 1.5 watts which is greater than 1 watt

3)

V = i*Rnet = 100*10^-3*(10+50) = 6 volts

V1 = i*R1 = 0.1*10 = 1 volt

v2 = i*r2 = 0.1*50 = 5 volts


4)

Rnet = R1*R2/(R1+R2) = 10*50/(10+50) = 8.333 ohms

I = V/Rnet = 0.36 A

i1(current through 10 ohms) = R2*I/(R1+R2) = 50*0.36/(10+50) = 0.3 A

i2(current through 50 ohms) = R1*I/(R1+R2) = 10*0.36/(10+50) = 0.06 A

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