On average, an electric water heater operates for 1.6 h each day. It has a power

Question

On average, an electric water heater operates for 1.6 h each day. It has a power requirement of 4500 W and a current requirement of 37.5 A when wired to a 240 V household supply.

On average, an electric water heater operates for 1.6 h each day. It has a power requirement of 4500 W and a current requirement of 37.5 A when wired to a 240 V household supply. If the cost of electricity is $0.28/kWh, what is the cost of operating the heater during a 30-day month? ___ $ What is the resistance of a typical water heater? ___

Explanation / Answer

Energy Required in one day = power * time = 4500*1.6/1000 = 7.2kWh

so cost of operating heater for 30 days = 7.2*30*0.28 = 60.48$

the numbers are not correct. 240 volts x 37.5 amps = 9000 watts. If you are listing the problem correctly, then there is a mistake in the problem, in the book, or your teach made a mistake.

But you can use 4500 watts and 240 volts to get
P = E

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