A capacitor of capacitance C is connected to a battery with voltage V and allowe

Question

A capacitor of capacitance C is connected to a battery with voltage V and allowed to fully charge.  The battery is then disconnected.  with the battery disconnected, the plates are moved apart to twice their original distance.  Give the charge, voltage and capacitance of the capacitor after the plates are moved in terms of C and V.

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Explanation / Answer

at the time of fully charged, Q = C*V C = e0*A/d the same charge will also remain later(when d'= 2d) Q' = Q d'= 2d C' = e0*A/d' = e0*A/2d = C/2 C' = Q'/V' => C/2 = Q/V' => V' = 2Q/C = 2V

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