If Luis pulls straight down on the end of a wrench that is tilted ? = 30 ? above

Question

If Luis pulls straight down on the end of a wrench that is tilted ?=30? above the horizontal and is r = 35cm long, what force must he apply to exert a torque of -17N?m?

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If you can explain how to do this because I am extremely lost!

If Luis pulls straight down on the end of a wrench that is tilted ?=30? above the horizontal and is r = 35cm long, what force must he apply to exert a torque of -17N?m? If you can explain how to do this because I am extremely lost!

Explanation / Answer

Torque T = Fr = N cos(theta) r = - 17 N-m; where N is the straight downward force, theta = 30 deg is the angle of the lever wrt horizontal, and r = .35 meters. The F = N cos(theta) factors make F the force perpendicular to the lever arm r.

Solve for N = - 17/(cos(theta) r) = -17/(cos(30)0.35) = -56.085 N

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