When a hammer strikes a nail, it is compressed along its length. Suppose that a

Question

When a hammer strikes a nail, it is compressed along its length. Suppose that a steel nail 10.00 cm long and 3.00 mm in diameter is compressed an average of 65.0 µm by a 0.415 kg hammer during a 1.20 ms collision. (a) What average force was exerted on the nail by the hammer? (b) What is the impulse imparted to the hammer? (c) If the hammer is moving at 7.00 m/s just before the collision, what is its final velocity?

a is not 872.5, b is not 1.05, and c is not 0

Explanation / Answer

Impulse = Change in Momentum
F(0.075 s) = 1.5kg(-4.5 m/s - 4.5 m/s)
F = 1.5(-4.5-4.5)/0.075
F = - 180 N answer

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