Direction of Magnetic Force A negative charge of -q = -2.9 times 10-19 C and m =

Question

Direction of Magnetic Force

A negative charge of -q = -2.9 times 10-19 C and m = 2.7 times 10-28 kg enters a magnetic field B = 0.6 T with initial velocity v = 220 m/s as shown in the figure. The magnetic field points inside the screen. -q = -2.9 times 10-19 C m = 2.7 times 10-28 kg B = 0.6 T v = 220 m/s Part (a) Which direction will the magnetic force be on the charge? 1) To the right. 2) Downward. 3) To the left. 4) Upward. 5) Into the screen. 6) Out of the screen. Part (c) Calculate the numerical value of the magnitude of force F in N. F = __ Part (d) Under such a magnetic force, which kind of motion will the charge undergo? 1) Uniform Circular motion.

Explanation / Answer

a. downward

c. F=qvB

F=-2.9*10^-19*220*0.6

F=-3.81*10^-17N
d.uniform circular motion

f. F= ma = -3.81*10^-17

a = 3.81*10^-17/2.7*10^28

a=-1.41*10^11 m/s^2

f.g. centripetal force = magnectic force

mv^2/R = qvB

R=mv/qB

h.R=2.7*10^-28 * 220/(2.9*10^-19*0.6)

R=3.41*10^-7 m

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