A single turn coil of radius 4.50 cm is held in a vertical plane and a magnet is

Question

A single turn coil of radius 4.50 cm is held in a vertical plane and a magnet is rapidly moved relative to the coil as shown in the diagram below.

The field inside the coil changes from 0.510 T to 0.365 T in 0.120 s. If the resistance of the coil is 2.70 ?, what are the magnitude and direction of the induced current in the coil as viewed from the side of the magnet?

magnitude _____________ mA

direction _______________

A single turn coil of radius 4.50 cm is held in a vertical plane and a magnet is rapidly moved relative to the coil as shown in the diagram below. The field inside the coil changes from 0.510 T to 0.365 T in 0.120 s. If the resistance of the coil is 2.70 ?, what are the magnitude and direction of the induced current in the coil as viewed from the side of the magnet?

Explanation / Answer

induced emf e is given by e=NAdB/dt

where N = no. of turns, A= area of the coil = pi r^2, dB/dt is the rate of change of magnetic field

so e = 1 * 3.14* 0.045*0.045*(0.51-0.365)/0.12

e =0.00765 T

now induced currrent i = e/R where R = resistance

i = 0.00765/2.7

i = 2.84 mA

direction is clock wise

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