A 49.3-g golf ball is driven from the tee with an initial speed of 51.6 m/s and

Question

A 49.3-g golf ball is driven from the tee with an initial speed of 51.6 m/s and rises to a height of 33.4 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 6.98 m below its highest point?

A 49.3-g golf ball is driven from the tee with an initial speed of 51.6 m/s and rises to a height of 33.4 m. (a) Neglect air resistance and determines the kinetic energy of the ball at its highest point. (b) What is its speed when it is 6.98 m below its highest point?

Explanation / Answer

KE f = 1/2mVo2 - mgh

0.5x0.0493(51.6)^2 - 0.0493x9.81x33.4 = 49.4787618J

Vf = sq root (51.6^2 - 2(9.81x26.42)) = 46.3055029127m/s

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