At a certain location, the horizontal component of the earth\'s magnetic field i
ID: 2144625 • Letter: A
Question
At a certain location, the horizontal component of the earth's magnetic field is 2.3x10-5 T, due north. A proton moves eastward with just the right speed, so the magnetic force on it balances its weight. Find the speed of the proton.
_____________ m/s
At a certain location, the horizontal component of the earth's magnetic field is 2.3x10-5 T, due north. A proton moves eastward with just the right speed, so the magnetic force on it balances its weight. Find the speed of the proton. _____________ m/sExplanation / Answer
qVB = mg
1.6 * 10^-19 * V * 2.3 * 10^-5 = 1.67 * 10^-27 * 9.8
v = (1.67 * 10^-27 * 9.8)/(1.6 * 10^-19 * 2.3 * 10^-5) = 4.44 * 10^-3 m/s
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