A 4.00-kg object undergoes an acceleration given by a= (6.00 i+ 2.00 j) m/s2. Fi

Question

A 4.00-kg object undergoes an acceleration given by a= (6.00 i+ 2.00 j) m/s2. Find the resultant force acting on the object. Find the magnitude of the resultant force. The average speed of a nitrogen molecule in air is about 6.70 ? 102 m/s, and its mass is about 4.68 ? 10-26 kg. If it takes 4.10 ? 10-13 s for a nitrogen molecule to hit a wall and rebound with the same speed but moving in an opposite direction (assumed to be the negative direction), what is the average acceleration of the molecule during this time interval? What average force does the molecule exert on the wall? A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, taken as the xy plane. The 4.60-kg puck has a velocity of2.00  I m/s at one instant. Eight seconds later, its velocity is (6 i + 12 j) m/s. Assuming the rocket engine exerts a constant horizontal force, find the components of the force. Find its magnitude. The gravitational force exerted on a baseball is 2.31 N down. A pitcher throws the ball horizontally with velocity 14.0 m/s by uniformly accelerating it along a straight horizontal line for a time interval of 152 ms. The ball starts from rest. Through what distance does it move before its release? What are the magnitude and direction of the force the pitcher exerts on the ball?

Explanation / Answer

Too many questions to be solved for 750 points... Here I go still :

1)

a) F = m * a = 4 * (6i + 2j) = (24i + 8j) N

b) Magnitude of resultant force = sqrt(24^2 + 8^2) = 25.3 N

Direction = arctan(8/24) in degrees = 18.434 degrees.

2)

a) 2mv = F.t

F = 2mv/t

Hence acceleration = 2v/t = (2 * 6.7 * 10^2)/(4.1 * 10^-13) = 3.27 * 10^15 m/s^2

b) Average force = ma = 4.68 * 10^-26 * 3.27 * 10^15 = 1.53 * 10^-10 N

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