Future space stations will create an artificial gravity by rotating. Consider a

Question

Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 870 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 870 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? 59 s 9.4 s 42 s 6.6 s Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 870 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 870 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? 59 s 9.4 s 42 s 6.6 s Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 870 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? 59 s 9.4 s 42 s 6.6 s Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 870 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? 59 s 9.4 s 42 s 6.6 s Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station of 870 m diameter rotating about its axis. Astronauts walk on the inside surface of the space station. What rotation period will provide "normal" gravity? 59 s 9.4 s 42 s 6.6 s 59 s 9.4 s 42 s 6.6 s

Explanation / Answer

The centripetal accleration a =?2.R will provide artificialgravity. Therefore, a =?2.R = g = 9.8m/s2 Hence, ? =2?/T = ?g/R =?9.8/435= 0.1500957548772913

And the time period T = 2 ?/? =2?/?g/R = 2x3.14/0.1500957548772913 = 41.84016789366734 = 42s. The choice (c) is correct.

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