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Show work please On the planet Kermit, in the Muppet population, there are two a

ID: 214716 • Letter: S

Question

Show work please

On the planet Kermit, in the Muppet population, there are two autosomal loci of interest. The first locus has alleles A and a, and the second locus has alleles B and b. Both code for hair color: Locus 01 A Blue hair; a Green hair Locus 02 B Blue hair; b Green hair. The A and B alleles are dominant for their respective loci. Suppose an aaBB Muppet male mates with an AAbb Muppet female. The couple produces multiple offspring, and a pair of the F1 Muppets intercross to produce several hundred offspring offspring. The counts for each pair of phenotypes are as follows: Table 1.Counts of F2 phenotype pairs from F1 Muppet intercross Phenotype pair Green Hair Blue Hair Count 1521 The results presented in Table 1 suggest that: 0 A. Locus 01 and Locus 02 act in a duplicate dominant epistatic manner in this population. B. Locus 01 and Locus 02 act in a dominant epistatic manner in this population. C. There is O recombination between Locus 01 and Locus 02. D. Locus 01 and Locus 02 act in a non-epistatic manner in this population. E. Locus 01 and Locus 02 act in a duplicate recessive epistatic manner in this population.

Explanation / Answer

Option A is the correct answer.

Here the cross between aaBB (gamete aB) and AAbb (gamete Ab) will produce all F1 progeny with AaBb genotype.

Intercross of F1: AaBb X AaBb should produce phenotypic ratio 9:3:3:1 in case of non-epistatic condition according to Mendelian genetics. But here the obtained phenotypic ratio is almost 15: 1 which indicate duplicate dominant epistasis. When a dominant allele at either of two loci can mask the expression of recessive alleles at the two loci, it is known as duplicate dominant epistasis.

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