Thanks you A piece of glass has a temperature of 89.9degree C. Liquid that has a

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A piece of glass has a temperature of 89.9degree C. Liquid that has a temperature of 43.0degree C is poured over the glass, completely covering it, and the temperature at equilibrium is 53.1degree C. The mass of the glass and the liquid is the same. Ignoring the container that holds the glass and liquid and assuming that the heat lost to or gained from the surroundings is negligible, determine the specific heat capacity of the liquid. (See Table 12.2 for appropriate constants.) J/(kg . C degree)

Explanation / Answer

Heat lost by glass=mcT=m*840*(89.9-53.1)=30912m

Heat gained by liquid=mcT=m*c*(53.1-43)=10.1cm

Equating these,

10.1cm=30912m

c=3061j/KgC

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