OK, so I\'ve been working on this one, I got the first half finished, but I\'m n

Question

OK, so I've been working on this one, I got the first half finished, but I'm not even sure how to write the equation for the secong half... here it is:

Charge q_1 = 6.95e-6 C is at the origin, and charge q_2 = -5.05e-6 C is on the x-axis, 0.300 m from the origin

So that's what I've got figured out, answers have been input and accepted. Heres my trouble:

(c) Place a charge of -5.00e-6 C at point P and find the magnitude and direction of the electric field at the location of q_2 due to q_1 = 6.95e-6 C and the charge at P.

(d) Find the magnitude and direction of the force on q_2.

Explanation / Answer

ok when you place charge -5.00e-6 at the P point then electric field at the location of q_2 due to P is :
E1 = k * - 5.00 * 10^-6 / 0.25 = 178 * 10^3 N/C
its direction is outwards from q_2

electric field at q_2 location due to q_1 is :
E2 = k * 6.95 * 10^-6 / 0.09 = 687.27 * 10^3 N/C
its direction is inwards towards q_1

angle between E1 and E2 is :
(90 - ) + 90 = 180 -

resultant electric field at q_2 is :

(c) E = sqrt (E1^2 + E2^2 + 2*E1*E2 cos (180 - ) )
= 567.68 N/C

by tan @ = E2/E1
we can find @

(d) for d part
force F1 = 5.05 * 10^-6 * E1
direction will be same as E1

force F2 = 5.05 * 10^-6 * E1  
direction will be same as E2

calculate resultant force

angle between the resultant force will be same as between E1 and E2

thanks!!!

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