The jumping gait of the kangaroo is efficient because energy is stored in the st

Question

The jumping gait of the kangaroo is efficient because energy is stored in the stretch of stout tendons in the legs; the kangaroo literally bounces with each stride. We can model the bouncing of a kangaroo as the bouncing of a mass on a spring. A 82kg kangaroo hits the ground, the tendons stretch to a maximum length, and the rebound causes the kangaroo to leave the ground approximately 0.15s after its feet first touch.

The period calculated is 0.3s

Given the kangaroo mass and the period you've calculated, what is the spring constant?

Explanation / Answer

82*(2*/0.3)235969 or 3.6 E4 N/m=k

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