A copper (Young\'s mudulus 1.1 x 1011 N/m2) cylinder and a brass (Young\'s mudul

Question

A copper (Young's mudulus 1.1 x 1011 N/m2) cylinder and a brass (Young's mudulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.41 cm. A compressive force of F = 9000 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases

A copper (Young's mudulus 1.1 x 1011 N/m2) cylinder and a brass (Young's mudulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.41 cm. A compressive force of F = 9000 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases

Explanation / Answer

Change in length = (FL/AY)copper + (FL/AY)brass

A = *(0.41^2) = 0.527834 cm^2 = 0.527834 *10^-4 m^2

So, change in length = 9000*0.03/(0.527834 *10^-4 *1.1*10^11) + 9000*0.05/(0.527834 *10^-4 *9*10^10)

= 1.4123*10^-4 m = 0.14123 mm

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