In the figure, the ideal batteries have emfs 1 = 7.0 V and 2 = 0.5001, and the r

Question

In the figure, the ideal batteries have emfs 1 = 7.0 V and 2 = 0.5001, and the resistances are each 3.50 ?.

http://www.webassign.net/hrw/hrw7_27-35.gif

(a) What is the current in resistor 2?
A

(b) What is the current in resistor 3?
A

Explanation / Answer

e1 = 7 V e2 = 3.5 V r1=r2=r3 = 3.50 ohms let i is the current driven from battery 1 let current in 2 resistor is i2 , in 3 resistor is i3 applying kcl at node , i = i2 + i3 applying kvl in right side loop +3.5 + i2 * 3.5 - i3 * 3.5 = 0 => i2 - i3 = -1 ........................................(1) applying kvl in left side loop ir1 - E1 + i3r3 = 0 (i2 + i3)3.5 - 7 + i3 * 3.5 = 0 => 7 * i3 + 3.5 * i2 = 7 => i2 + 2 * i3 = 2 ..........................................(2) solving (1) and (2) i3 = 1 A , current in resistor 3 i2 = 0 A , current in resistor 2

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