Two parallel current carrying wires are separated by 12 cm and each are 50 cm in

Question

Two parallel current carrying wires are separated by 12 cm and each are 50 cm in length. The currents travel in the same direction for each wire (coming out of the page). One wire (on the left) has a current of 4 A and the other wire's current is 6 A.
a) Determine the Force acting each wire due to the other one:
b) Determine the location directly between the wires such that the Net Vertical Magnetic Field is Zero:
i.e. Bnet= B1 + B2 = 0

Explanation / Answer

a) F = 4*3.1416e-7*L i1 i2/2 pi r = 4*3.1416e-7*0.50*4*6/(2*3.1416*0.12) = 2e-5 N b) 4*3.1416e-7*i1 /2 pi r1 = 4*3.1416e-7*i2 /2 pi r2 i1/r1 = i2/r2 4/r1 = 6/r2 >>> r2 = 1.5 r1 r1 + r2 = 0.12 r1 + 1.5 r1 = 0.12 >>> r1 = 0.048 m 0.048 m from the wire on the left

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