Problem Suppose the mirror is 1.5 m above the floor. The reflected ray of sunlig

Question

Problem Suppose the mirror is 1.5 m above the floor. The reflected ray of sunlight strikes the floor at a distance of 3.5 m from the base of the wall. Later in the morning, the ray is observed to strike the floor at a distance of 2.0 m from the wall. The earth rotates at a rate of 15.0? per hour. Mirror is situated in some place on the equator at the time of the equinox.

(b1) What is the time t that has elapsed between the two observations of where the sunlight strikes the floor after reflecting from the mirror?

Explanation / Answer

the distance is d1 = 3.5 m later the distance is d2 = 2.0 m speed of rotation of earth is v = 15.0 m per hour = (15.0/3600) m/second the time taken to cover the first distance is t1 = d1/v the time taken to cover the second distance is t2 = d2/v time elapsed between the two observations is delta(t) = t1 - t2

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