Two equal masses (1 and 2) are connected by a rope across a pulley and placed on
ID: 2155648 • Letter: T
Question
Two equal masses (1 and 2) are connected by a rope across a pulley and placed on larger block A as shown on the picture.
The coefficient of kinetic friction between each of the masses and block A is u, the rope has no mass and can not be stretched.
Find the minimal acceleration a of block A along the horizontal so that masses 1 and 2 remain stationary with respect to block A.
Explanation / Answer
Due to acceleration of A there will be a pseudo force on 1 and 2 in opposite direction. Let mass of 1 and 2 be m Let a be the acceleration of A Then forces on 1 and 2 => ma Now Friction on mass 1 + pseudo force = tension in rope (so the they remain stationary) => umg + ma = T ....1 For mass 2 Friction = Tension uma = T...2 using 1 and 2 umg + ma = uma => a = ug/(u - 1)
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