A capacitor is constructed from two metal sheets placed 1.5 mm apart. The total
ID: 2156193 • Letter: A
Question
A capacitor is constructed from two metal sheets placed 1.5 mm apart.
The total capacitance is 16 pF (16?10-12 F).
A battery is used to charge the capacitor to 10 nC (10?10-9 C).
the area of the plate is 0.0027m^2
The positive and negative plates are shown:
1) What direction do the electric field lines point inside the capacitor shown?
2) What is the strength of the electric field between the plates?
3) If 3 of these capacitors are connected in parallel and then this combination is connected in series with a forth capacitor, what is the net capacitance of the combination?
can you solve this problem step by step? (at least, give me an hint of what equation to be used)
Explanation / Answer
(1) Direction of electric Field is Fron Positive(+ve) to Negative(-ve)
(2)Strength of Electric Field = /
= ((10*10^-9)/0.0027)/(8.854*10^-12)
= 4.183*10^5 N/C
Net Capictance in parallel Capacitors = (16*3*10^-12)
= 48*10^-12 F
It is in series with the Capactor
So required Net Capictance = (48*10^-12*16*10^-12)/(16*10^-12 + 48*10^-12)
= 1.2*10^-11 F
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