Two slits separated by a distance of d = 0. 13mm are located at a distance of D

Question

Two slits separated by a distance of d = 0. 13mm are located at a distance of D = 580mm from a screen. The screen is oriented parallel to the plane of the slits. The slits are illuminated by a coherent light source with a wavelength of lambda = 529E-6 mm. The interference pattern shows a peak at the center of the screen (m=0) and then alternating minima and maxima. What is the pathlength difference between the two waves from the two slits at the first (m=1) maximum on the screen? Answer: What is the pathlength difference between the two waves from the two slits at the first (m=0) minimum on the screen? Calculate the distance on the screen between the central maximum (m=0) and the first (m=1) maximum (You can assume sin( theta ) = tan( theta ) = theta with theta expressed in radians). Answer:

Explanation / Answer

a)Path difference==529*10-6mm=529*10-9m

b)Path difference=/2=264.5*10-6mm=264.5*10-9m

c)y=D/d

D=distance between screen and slits.

d=distance between slits.

y=580*529*10-6/0.13=2.36mm=2.36*10-3m

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