What is the least amount of energy, in electron volts, that must be given to a h

Question

What is the least amount of energy, in electron volts, that must be given to a hydrogen atom which is initially in its ground level so that it can emit the H alpha line in the Balmer series?


Emin=12.08 _Ev


How many different possibilities of spectral-line emissions are there for this atom when the electron starts in the n= 3.00 level and eventually ends up in the ground level?

Give your answer as a number having no units.

___3___



Part C

Calculate the wavelength of the emitted photon in each case.

Enter your answers in increasing order, separate them with commas.


wavelength1, wavelength2, wavelength3=___________________?

Explanation / Answer

the balmer series of emission is the transmission of electron from any level n> or = 3 to state below it . h alfa line is the the transmission of e from n=3 to n=2 so the least energy required to get the electron to make a h alpha emission is the energy required to get the electron to go to n= 3 state. E = 13.6 ( 1/n1^2 - 1/n2^2) n1= 1 n2 = 3 substuting we get, E = 12.08 eV. the possible spectral emissions are, n3 to n1 n3to n2 n2 to n1 so the number is 3 wavelength of emitted photon in each case is, n3 to n1 : 1/? = Rh ( 1/n1^2 -1/n2^2) n1= 1 n2=3 substituting and calculating, we get, ? = 102.2 nm n3 to n2 ==> n1 = 2, n2 = 3 substuting and calculating, ? = 654.54 nm. n2 to n1 n1 = 1 n2 = 2 substuting and calculating, ? =121.2 nm. so answers in incresing order is 102.2 nm, 121.2 nm, 654.54 nm..

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