Trial Number <?xml:namespace prefix = o ns = \"urn:schemas-microsoft-com:office:

Question

Trial Number <?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /?>

Maximum Height (m)

Time in Air (s)

1

<?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /?>

1.397

2

1.473

1.00

3

1.245

.89

4

1.575

.96

Average

1.423

.95

1. What is the gravitational potential energy your popper has at its maximum height you measured? Use g = 9.8 m/s, and a mass of 0.01 kg.

2. Use the following kinematics equations from Labs 4 and 5 to calculate the initial velocity of the popper based on the time ( t ) it is in the air:

h=h0 + v0t

Trial Number <?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /?>

Maximum Height (m)

Time in Air (s)

1

<?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /?>

1.397

5555

.93

2

1.473

1.00

3

1.245

.89

4

1.575

.96

.9.

Average

1.423

.95

.95

Explanation / Answer

V=mgh =0.01*9.8*1.575 =0.15435J Vo=gt/2 for lab4, Vo=9.8*1.86/2=9.114 for lab5, Vo=9.8*1.9/2=9.31 K.E=0.5*m*v^2 =0.4153 no more. because some energy is consumed by air resistance

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