In an experiment with photoelectric effect, electrons are ejected from a metalli

Question

In an experiment with photoelectric effect, electrons are ejected from a metallic surface with speeds up to 6.314 105 m/s when light with a wavelength ?1 = 206.0 nm is used. Find the maximum speed of photoelectrons when the wavelength of the incident light is reduced to ?2 = 151.4 nm.

Explanation / Answer

k.e. = (6.62*10^-34*3*10^8)/(206*10^-9) - work function =>work function = (6.62*10^-34*3*10^8)/(206*10^-9) - (0.5*9.109*10^-31*6.314*6.314*10^10) = 4.89eV Now for wave length of 151.4nm k.e. = (6.62*10^-34*3*10^8)/(151.4*10^-9) - (4.89*1.602*10^-19) = 5.296*10^-19J 0.5*9.109*10^-31*v^2 = 5.296*10^-19 v = 1.0783*10^6 m/sec

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