Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 22.0 m/s at an angle 60.0 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.
After catching the ball, Sarah throws it back to Julie. The ball leaves Sarah's hand a distance 1.5 meters above the ground, and is moving with a speed of 12.0 m/s when it reaches a maximum height of 23.0 m above the ground.

What is the speed of the ball when it leaves Sarah's hand
How high above the ground will the ball be when it gets to Julie? (note, the ball may go over Julie's head

Explanation / Answer

T=2vsin/g=2.422s

distance d= vcos*T=17.975 m

ucos=d/1.796 = 10s

11=usin*1.796^2/2g=> usin=66.83

dividing we get tan=6.68 , =81.49

velocity =67.57 m/s

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