A 1.5 Kg iron kettle containing 0.50 liters of water is placed on top of a gas r

Question

A 1.5 Kg iron kettle containing 0.50 liters of water is placed on top of a gas range. The intial temperature of the kettle plus water is 20 degrees celcius. You turn on the burner, and 8.0 minutes later the kettle and water are at a temperature of 95 degrees celcius. What was the rate of transfer of heat into the kettle/water system? In other words, find delta Q/delta T, whihc has units of power (watts). Assume that no heat is lost by the kettle, which is not entirely realistic.

Explanation / Answer

Q = m c delta(T) => Q = 156900j P = Q / t = 326.875 watt

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