Three point charges lie along a straight line as shown in the figure below, wher

Question

Three point charges lie along a straight line as shown in the figure below, where q1 = 6.12 mu C, q2 = 1.48 mu C, and q3 = -2.12 mu C. The separation distances are d1 = 3.00 cm and d2 = 2-00 cm- Calculate the magnitude and direction of the net electric force on each of the charges. q1 magnitude Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. N direction q2 magnitude N direction q3 magnitude N direction

Explanation / Answer

F1 = F21 + F31, (in other words the force acting on charge 1 is equal the force of charge 2 on 1, plus the force of charge 3 on 1) After establishing this you go on to use the Electric Force Equation, which is: F=(ke * q1*q2)/ r^2 where ke=8.988*10^9 N*m^2/C^2 and r is the distance between the two charges. Do not forget to first conver the units of the charge and distance to the proper SI units of Coulomb and meter. F=F21+F31 =9*10^9 *(6.12 * 10^-8 * 1.42 * 10^-8/9 - 2.12 * 10^-8 *6.12*10^-8/25) =4.02 *10^-3 The direction can be determined based on the diagram, if two charges are alike then the force would point towards the other force, and if the charge are not alike then the force would point towards itself.

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