A car travels along a straight line at a constant speed of 46.5 mi/h for a dista

Question

A car travels along a straight line at a constant speed of 46.5 mi/h for a distance d and then another distance d in the same direction at another constant speed. The average velocity for the entire trip is 28.5 mi/h. What is the constant speed with which the car moved during the second distance d? mi/h Suppose the second distance d were traveled in the opposite direction; you forgot something and had to return home at the same constant speed as found in part (a). What is the average velocity for this trip? mi/h What is the average speed for this new trip? mi/h

Explanation / Answer

28.5 = d/46.5 +d/ x => d(46.5x /46.5+x) =28.5 solving for x we get the distance average speed = 2d/total time

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.